Question

ex nr.7 pls pls pls pls pls pls

Answer 1

Salut,

m ÷ 25 = 356, rest 3
m = ( 356 × 25 ) + 3
m = 8 900 + 3
m = 8 903
8 903 ÷ 25 = 356, rest 3

739 ÷ n = 5, rest 4
n = ( 739 - 4 ) ÷ 5
n = 735 ÷ 5
n = 147
739 ÷ 147 = 5, rest 4

p ÷ 63 = 809, rest 14
p = ( 809 × 63 ) + 14
p = 50 967 + 14
p = 50 981
50 981 ÷ 63 = 809, rest 14

804 ÷ q = 16, rest 4
q = ( 804 - 4 ) ÷ 16
q = 800 ÷ 16
q = 50
804 ÷ 50 = 16, rest 4

y ÷ 47 = 219, rest 12
y = ( 219 × 47 ) + 12
y = 10 293 + 12
y = 10 305
10 305 ÷ 47 = 219, rest 12

1 268 ÷ z = 62, rest 28
z = ( 1 268 - 28 ) ÷ 62
z = 1 240 ÷ 62
z = 20
1 268 ÷ 20 = 62, rest 28

$Eckram$

Answer 2

Răspuns

Explicație pas cu pas:

m\25=356 rest3

m=356*25+3

m=8900+3

m=8903

8903\25=356 rest 3

739\n=5 rest4

739=5n+4

5n=739-4

5n=735

n=735\5

n=147

739\147=5 rest 4

p\63=809 rest 14

p=63*809+14

p=50.967+14=50.981

50.981\63=809 rest14

804\q=16 rest4

804=16q+4

804-4=16q

800=16q

q=800\16=50

q=50

804\50=16 rest 4

y\47=219 rest 12

y=47*219+12=10293+12=10305

y=10305

10305\47=219+12

1268\z=62 rest 28

1268=62z+28

1268-28=62z

1240=62z

z=1240\62=20

z=20

1268\20=62 rest 28