Question

Ex1) 1 \frac{1}{6} · \frac{3}{5} - \frac{1}{2}

ex2) a= \frac{3}{8}
b+c= 1 \frac{1}{9}
a·b+a·c=?

Answer 1

[tex]\it b+c = 1\dfrac{1}{9} = \dfrac{10}{9} \\\;\\ \\\;\\ a\cdot b + a\cdot c = a(b+c) = \dfrac{3}{8}\cdot\dfrac{10}{9} = \dfrac{\ \ 30^{(6}}{\ 72} = \dfrac{5}{12}[/tex]

Answer 2

        a = 3/8 
 si  b+c = (9*1+1)/9 = 10/9

=> a*b+a*c = a*(b+c) = 3/8 * 10/9  = 30/72 = 15/36 = 5/12;