Question

ex1: rezolvati ecuatiile: a) 136-(43-x)=102 b) (61+x)-35=269 c) (112-x)-54=28 d) (83+x)-30=424-301 e) (x-36)-36=36 f) (124-x)-53=50
ex2: suma a doua numere naturale este cel mult 2010, iar diferenta lor este cel putin 2010. aflati cele doua numere

Answer 1

a)136-(43-x )=102
136-43+x =102
x =102-136+43
x =9
b)(61+x )-35 =69
61+x -35 =69
x =69-61+35
x =43
c) (112-x )-54 =28
112-x -54 =28
x =112-54-28
x =30
d)(83.+x )-30 =424-301
83+x -30 =424-301
x =424-301+30-83
x =70
e)(x-36 )-36 =36
x -36-36 =36
x =36+36+36
x =108
f) (124-x )-53 =50
124-x -53=50
x =124-53-50
x =21