Matematică, întrebare adresată de iovuo02, 8 ani în urmă

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Anexe:

Răspunsuri la întrebare

Răspuns de pav38
6

a)

\bf 3,75 - 2;0,25+1,4\cdot3,55+1,2^{3}=

\bf 3,75 - 8+4,97+1,2\cdot 1,2\cdot1,2 =

\bf 3,75 - 8+4,97+1,728=

\bf 10,448 - 8=

\boxed{\bf 2,448} sau \bf \dfrac{2448}{1000} =  \dfrac{\not2448}{\not 1000}=\boxed{\bf \dfrac{306}{125}}

b)

\bf 6,24:0,4 +7,65\cdot20 - 1000\cdot 0,01\cdot 5^{2}=

\bf 15,6 +153 - 1000\cdot 0,01\cdot 25=

\bf 15,6 +153 - 250=

\bf 168,6 - 250=

\boxed{\bf -81,4} sau \bf -\dfrac{814}{10} =  -\dfrac{\not814}{\not 10}=\boxed{\bf -\dfrac{407}{5}}

c)

\bf 3 \dfrac{1}{4}\cdot 2 \dfrac{5}{8}-15\dfrac{1}{2}: 3 \dfrac{3}{4}+\dfrac{62-6}{9}\cdot \dfrac{9}{23}-11^{2}\cdot 10^{2}=

\bf  \dfrac{13}{4}\cdot \dfrac{21}{8}-\dfrac{31}{2}: \dfrac{15}{4}+\dfrac{56}{9}\cdot \dfrac{9}{23}-(11\cdot 10)^{2}=

\bf  \dfrac{273}{32}-\dfrac{31}{2}\cdot\dfrac{4}{15}+\dfrac{56}{\not9}\cdot \dfrac{\not9}{23}-110^{2}=

\bf  \dfrac{273}{32}-\dfrac{62}{15}+\dfrac{56}{23}-12100=

\bf  \dfrac{273\cdot 15\cdot23- 62\cdot32\cdot23+56\cdot32\cdot15-12100\cdot 15\cdot23\cdot32}{11040}=

\bf  \dfrac{94185- 45632+26880-133584000}{11040}=

\boxed{\bf - \dfrac{133508567}{11040}}

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