Question

Ex6 repede va rog frumos

Answer 1

Introducem factorii sub radical, pt a compara mai usor.

a) 3√6 = √(3² * 6) = √(9*6) = √54

5√2 = √(5² * 2) = √(25*2) = √50

Pe 7 il scriem √49

4√3 = √(4² * 3) = √(16*3) = √48

2√13 = √(2² * 13) = √(4*13) = √52

Acum putem ordona => √48 < √49 < √50 < √52 < √54

b) 8√2 = √128

5√5 = √125

11 = √121

2√30 = √120

2√31 = √124

=> √120 < √121 < √124 < √125 < √128

c) 4√10 = √160

5√6 = √150

12 = √144

7√3 = √147

9√2 = √162

=> √144 < √147 < √150 < √160 < √162

d) 19 = √361

15√2 = √450

6√10 = √360

10√3 = √300

12√3 = √432

=> √300 < √360 < √361 < √432 < √450