Question

exercitii cu mersul invers 14+{4+[28+(a+2):6]-5}:5=37

Answer 1

[tex] 14+\{4+[28+(a+2):6]-5\}:5=37 \\ \{4+[28+(a+2):6]-5\}:5 = 37-14 \\ \{4+[28+(a+2):6]-5\}:5 = 23 \\ 4+[28+(a+2):6]-5= 23 \times 5 \\ 4+[28+(a+2):6]-5=115 \\ \ [28+(a+2):6] +4-5 = 115 \\ \ [28+(a+2):6]-1 = 115 \\ 28+(a+2):6 = 115+1 \\ 28+(a+2):6 = 116 \\ (a+2):6 = 116-28 \\ (a+2):6 = 88 \\ a+2 = 88\times 6 \\a+2= 528 \\ a = 528-2 \\ a = 526[/tex]