Question

Exerciții matematică clasa a 10-a​

Answer 1

1)

x²-(2m+1)+5m-4=0

$x_1^2+x_2^2=9\\\\S^2-2P=9$

$S=\frac{-b}{a} =\frac{2m+1}{1} =2m+1\\\\P=\frac{c}{a} =5m-4$

(2m+1)²-2(5m-4)=9

4m²+4m+1-10m+8=9

4m²-6m=0

2m(2m-3)=0

m=0 si $m=\frac{3}{2}$

2)

Notam lgx=a

a²-2a-3=0

Δ=4+12=16

a=3 si a=-2

lgx=3

x=1000

lgx=-2

x=10⁻²

3)

Conditia de perpendicularitate:

2m+4(m-1)=0

2m+4m-4=0

6m=4

$m=\frac{2}{3}$

Un alt exercitiu gasesti aici: https://brainly.ro/tema/3400928

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