Question

Exercitiile 1 si 2 .Va rog.​

Answer 1

Răspuns:

Pt cazurile 1 și 2 notam z cu t

1.

a. t²-10t+9=0

delta,triunghiul acela=100-36=64

t1=(10+8)/2=9

t2=(10-8)/2=1

b. t²-12t-64=0

delta= 144+256=400

t1=(12+20)/2=16

t2=(12-20)/2=-4

c. t²+17t+72=0

delta =289-288=1

t1=(-17+1)/2=-8

t2=(-17-1)/2=-9

d. 16t²+40t+9=0

delta=1600-576=1024

t1=(-40+32)/2=-4

t2=(-40-32)/2=-21

2.

a. t²-6t+25=0

delta= 36-100=-64

t1=(6+8i)/2=3+4i

t2=3-4i

b. t²-16t+100=0

delta =256-400=-144

t1=(16+12i)/2=8+6i

t2=8-6i

c. 16t²-24t+25=0

delta =576-1600=-1024

t1=(24+32i)/2=12+16i

t2=12-16i

d. 16t²+40t+169=0

delta=1600-10816=-9216

t1=(-40+96i)/2=-20+48i

t2=-20-48i