Question

exercitiile 11 si 12 va rog mult. ca nu mai țin minte nimic :(​

Answer 1

Vom inmulti in diagonala

11.

$\frac{x+1}{5}= \frac{3}{5} \\\\5(x+1)=5*3\\\\5x+5=15\\\\5x=15-5\\\\5x=10\\\\x=10:5\\\\x=2$

12.

$\frac{2x-5}{6} =\frac{1}{2} \\\\2(2x-5)=1*6\\\\4x-10=6\\\\4x=6+10\\\\4x=16\\\\x=16:4\\\\x=4$

Answer 2

11)

$\bf \dfrac{x+1}{5}=\dfrac{3}{5}$

cand numitorii sunt aceeasi se ezaleaza NUMARATORII

$\bf x+1=3$

$\bf x=3-1$

$\boxed{\bf x=2}$

12)

$\bf \dfrac{2x-5}{6} =\dfrac{1}{2}$

$\bf 2\cdot (2x-5)=1\cdot 6$

$\bf 2\cdot (2x-5)= 6\:\:\:|:2\:(impartin \:relatia\:cu\:2)$

$\bf 2x-5=3$

$\bf 2x=3+5$

$\bf 2x=8\:\:|:2$

$\boxed{\bf x=4}$