Question

exercitiile 2,3 și 5 sau doar unul dintre ele
repedeeeee dau coroană ​

Answer 1

Salut!

2.

a)$2^{3}$·$2^{3}$·$2^{0}$·$2^{1}$=$2^{3+3+0+1}$=$2^{7}$

b)$5^{3}$·$5^{5}$·$5^{1}$·$5^{10}$=$5^{3+5+1+10}$=$5^{19}$

c)$3^{3}$·$3^{1}$·$3^{2}$·$3^{4}$·$3^{0}$=$3^{3+1+2+4+0}$=$3^{10}$

d)$(2^{2})^2$·$(2^{3} )^3$·$2^{3}$·$2^{4}$=$2^{4+9+3+4}$=$2^{20}$

e)$47^{1}$·$47^{2}$·$47^{5}$=$47^{1+2+5}$=$47^{9}$

f)$5^{0}$·$5^{1}$·$5^{2}$·$5^{3}$·$5^{4}$=$5^{0+1+2+3+4}$=$5^{10}$

3.

a)32+216=248

b)25-9=16

c)8+16+2=26

d)196-100-64=32

e)32-8+1=25

f)343-196-7=140

h)64-27+1=38

g)1+5+25=31

i)8+125+6=139

5.

a)$2^{17}$·$2^{21}$=$2^{38}$

b)$3^{45}$·$3^{87}$·$3^{55}$=$3^{187}$

c)$7^{19}$·$7^{83}$·7=$7^{102}$

d)$2^{47}$:$2^{39}$=$2^{8}$

e)$5^{108} :5^{72} =5^{36}$

f)$2^{37}$·$2^{47}$:$2^{50}$=$2^{34}$

g)$(10^{12} )^1^5=10^{180}$

h)$(2^{17} )^8$·$2^{31}$=$2^{167}$

i)$3^{108} :(3^{15} )^6=3^{18}$

k)$(2^{10}* 3^{7} )^9 : (2^{5} *3^{6})^ 1^0=2^{90} *3^{63} :2^{50} *3^{60} =2^{40} *3^{3}$=$2^{40}$*27

Sper ca te-am ajutat!

P.S:Coroana?