Matematică, întrebare adresată de Tubi666, 9 ani în urmă

exercitiile 2 si 7 , daca vreti si celelalte . dau coronita!

Anexe:

Răspunsuri la întrebare

Răspuns de nitugheorghe57
1
a)√5²+(5²×3²)/4²=
√25+(25×9)/16=
√25+225/16=
√400+225/16=√625/16=25/4

b)√3²+3∧4/2∧4=
√9+81/16=
√144+81/16=
√225/16=15/4

c)√7²+(7²×4²)/3²=
√49+(49×16)/9=
√49+784/9=
√441+784/9=
√1225/3
succes


Răspuns de renatemambouko
1
(4 4/5 × 4 1/6 - 4 2/3 : 4/15 + 16 1/2)/(9 3/7-34/63 ×4 1/2) ×
×(8 3/5-2 1/5)/19 : 1 1/7=
=(24/5 × 25/6 - 14/3 ×15/4 + 33/2)/(66/7-34/63 ×9/2) ×
×(43/5-11/5)/19 ×7/8=
=(4/1 × 5/1 - 7/1 ×5/2 + 33/2)/(66/7-17/7 ×1/1) ×(32/5)/19 ×7/8=
=(20 - 35/2 + 33/2)/(49/7 ) ×(32/5)/19 ×7/8=
=(20 - 2/2 )/7  ×(32/5)/19 ×7/8=
=19/7  ×32/(5*19) ×7/8=
=1/1  ×4/5 ×1/1=4/5


√(5²+5²*3²/4²)=√(5²*4²+5²*3²)/4²=√5²(4²+3²)/4²=√5²(16+9)/4²=
=√5²*25/4²=√5²*5²/4²=5²/4=25/4=6,25


√(3²+3⁴/2⁴)=√(3²*2⁴+3⁴)/2⁴=√(3²(2⁴+3²)/2⁴=√(3²(16+9)/2⁴=√(3²*5²)/2⁴=
=3*5/2²=15/4=3,75

√(7²+7²*4²/3²)=√(7²*3²+7²*4²)/3²=√(7²*(3²+4²)/3²=√(7²*25)/3²=√(7²*5²)/3²=
=7*5/3=35/3=11,(6)


















Alte întrebări interesante