Question

Exercitiile 3 si 4 va rog mult! Dau coroana!

Answer 1

3. Cum vad eu problema

$\frac{x}{y} =0,2 => \frac{x}{y} =\frac{2}{10} =>10x=2y=>x=\frac{2y}{10}$

$\frac{5y-2x}{5y+2x}=\frac{5y-2(\frac{2y}{10}) }{5y+2(\frac{2y}{10}) } =\frac{5y-\frac{4y}{10} }{5y+\frac{4y}{10} }=\frac{\frac{46y}{10} }{\frac{54y}{10} } =\frac{46y}{54y} =\frac{46}{54} =\frac{23}{27}$

4.

$\frac{20}{100} *2750=2*275=550$