Question

exercitiile 3 si 5 de la teste please

Answer 1

Am atasat rezolvarea

Answer 2

$3).3(2x - 5) {}^{2} + 6 = 4 \\ 3(2x - 5) {}^{2} = 4 - 6 \\ 3(2x - 5) {}^{2} = - 2 \\ (2x - 5) {}^{2} = - \frac{2}{3} \\ x \: nu \: apartine \: lui \: r \\ \\ 5). \frac{x {}^{2} + 3x }{3} = \frac{2x + 2}{2} \\ \frac{x {}^{2} + 3x }{3} = \frac{2(x + 1)}{2} \\ \frac{x {}^{2} + 3x }{3} = x + 1 \\ x {}^{2} + 3x = 3x + 3 \\ x {}^{2} + 3x - 3x = 3 \\ x {}^{2} = 3 \\ x1 = - \sqrt{3} \\ x2 = \sqrt{3}$