Question

Exercitiile 4,5,6 sau macar unul dintre ele va roooog mult .. Multumesc :* !

Answer 1

1/1*2+1/2*3+...+1/n(n+1)=100/101
1/1-1/2+1/2-1/3+...+1/n-1/(n+1)=100/101
1-1/(n+1)=100/101
(n+1-1)/(n+1)=100/101
n/(n+1) =100/101
101n=100n+100
n=100


(5√3/√8+3√3/5√2-7√3/√2) :√3=
=5/2√2+3/5√2-7/√2=
=5√2/4+3√2/10-7√2/2=
=(25√2+6√2/10-70√2)/20=
=-39√2/20
n=-39√2/20
n√2=-39√2/20 *√2 =-78/20=-39/10=-3,9
partea intreaga -3


x-1/x=3
(x-1/x)=3²
x²-2*x *1/x +1/x²=9
x²-2+1/x²=9
x²+1/x²=11
11/300=0,03(6)=3,(6)%