Question

exercitiile 4 si 5, va rog!!
sunt pentru clasa a 10a

Answer 1

Răspuns:

Explicație:

4.   CH2=CH2+H2O---> CH3-CH2OH

    CH3-CH2OH+O2----> CH3COOH+H2O

   CH3COOH+CH3-CH3OH---> CH3COO-CH3-CH3(acetat de eiil)+H2O

M,C4H8O2=(4X12gC+8x1gH+2x16gO)/mol= 88g/mol

88g ester.....48gC......8gH.......32gO

100G.............X..............Y.................Z

X= 100X48/88g=........................calculeaza !!!!

Y=100X8/88g=............................

Z=100X32/88g=................................

5.formula chimica a acidului   CnH2nO2   cu masa molara M= 14n+32.g/mol

14n+32,g   ...........32gO

100G.................53,33gO

32OO=53,33(14n+32)--------> n=2---------> CH3COOH    cu M= 60g/mol

c= mdx100/ms----> md= 40x60/100g=24g ACID ACETIC

2x60g...................65g

2CH3COOH + Zn----> (CH3COO)2Zn      + H2

  24g.................x

m,Zn= 24x65/120g=....................calculeaza !!!!!      

p=m,px100/m,i---> m,p= 80x25/100g= 20g CaCO3 pur     cu    M=100g/mol

100g............2mol

CaCO3  + 2HCl----> CaCl2 +H2O+CO2

20g...........x=0,4molHCl

c=niu/V---> V= 0,4/4 l= 0,1 l= 100ml