Question

Exercitiile 5 si6 Subiect de bac

Answer 1

5) 2x - y = 6
-x + 2y = 6 | *2

2x-y=6
-2x+4y=12
---------------------
3y=18 => y = 6

2x-y=6; y=6
2x-6=6 =>x = 6.

x=y=6. Punctul de intersectie P(6,6)

AP= $\sqrt{(6-2)^2+(6-3)^2} = \sqrt{25} = 5$


6) $NP^2=NM^2+MP^2-2MN*MP*cos M$
$6^2=4^2+5^2-2*4*5*cos M$
40 * cos M = 5
cos M = $\frac{1}{8}$