Question

EXERCIŢIILE 6 ȘI 8!!!

Answer 1

6.
- 3≤ x-1 ≤ 0
x-1 ≤ 0
x≤1
A= [- 3; -2; -1; 0]

8.a)
2x+1≤1
2x≤ 1-1
2x≤0
x≤ 0
S=[ -∞; 0]
b)
x+1< 3x+5
x-3x <5-1
-2x <4
-x < 2
x > 2
S= (3;+∞)
c)
(3x+1) / 4≥ 1
3x+1≥4
3x≥4-1
3x≥3
x≥1
S=[1, +∞)
d)
x(1-√3) > 1-√3
x > (1-√3): (1-√3)
x > 1
S=(2;+∞)
e)
(x+1) / -2 ≥ 1
x+1≥ -2
x≥ - 2- 1
x≥ -3
S=[ -3; +∞)

f)
2*(x-√2)≤ √2x - 4
2x - 2√2≤ √2x -4
2x-√2x ≤  - 4 +2√2
x(2-√ 2) ≤ - 2*(2-√2) | : (2-√2)
x ≤  -2
S= ( -∞ ; -2]