Question

Exercitiile de pe poza va rog frumos

Answer 1

1.
MCH3Cl=50,5g/mol
MCH2Cl2=85g/mol

50,5x+85y............................35,5x+71y
100g........................................58g

2929x+4930y=3550x+7100y => 621x=2170y => x/y=2170/621=7/2

m CH3Cl=7*50,5=

m CH2Cl2=2*85=

2. C6H6 + 3Cl2 ---lumina---> C6H6Cl6 [gamexan sau lindan]

78g C6H6............................291g C6H6Cl6
xg C6H6..............................20g C6H6Cl6

x=78*20/291=5,36g C6H6

ro=m/V=>V=m/ro=5,36/0,79=