Question

Exercitile 24 si 25 va rog​

Answer 1

Sper sa iti fie de folos!

Scuze scrisul dezordonat..

Answer 2

Răspuns:

• 24.

AB ; AC ; BC d.p. cu 5 ; 12 ; 13 =>

AB/5 = AC/12 = BC/13 = k

AB = 5k

AC = 12k

BC = 13k

AB + AC + BC = 60

5k + 12k + 13k = 60

30k = 60

k = 2

AB = 5k = 10 cm

AC = 12k = 24 cm

BC = 13k = 26 cm

Verificam prin PITAGORA

BC² = AB² + AC²

676 = 576 + 100

676 = 676 (adevarat)

=> ΔABC = dreptunghic

• 25.

AM = DM = AD/2 = 12cm/2 = 6 cm

CN = CD - ND = 12cm - 3cm = 9 cm

calculam prin PITAGORA

BM² = AB² + AM² = 12² + 6² = 144 + 36 = 180

MN² = DN² + DM² = 6² + 3² = 36 + 9 = 45

BN² = BC² + CN² = 12² + 9² = 144 + 81 = 225

verificam prin Pitagora ΔBMN

BN² = BM² + MN²

225 = 180 + 45

225 = 225 (adevarat) =>

ΔBMN = dreptunghic