Question

Exercițiu 4 va rooog repede
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Answer 1

$_{_{27}}^{^{60}}Co\ \rightarrow27\ p^+\ ;\ (60-27)=33\ n^0\ ;\ 27\ e^-\\\\_{_{53}}^{^{137}}I\ \rightarrow53\ p^+\ ;\ (137-53)=84\ n^0\ ;\ 53\ e^-\\\\_{_{15}}^{^{32}}P\ \rightarrow15\ p^+\ ;\ (32-15)=17\ n^0\ ;\ 15\ e^-$

$_{_{Z}}^{^{A}}X\ \rightarrow\ Z: nr.\ p^+\ (protoni)\ =\ nr.\ e^-\ (electroni)\\ \/\ \/\ \/\ \/\ \/\ \/\ \rightarrow A: nr.\ p^+ + nr.\ n^0\ (neutroni)\\\\nr.\ n^0=A-Z$