Question

Exercitiu
[(9 pe 32 - 5 pe 24 - 7 pe 36) :(-7 pe 24) +0,(6)]- (2,1(6)) - 0,41(6)

Answer 1

[tex][( ^{9)}\frac{9}{32}- ^{12)} \frac{5}{24}-^{8)} \frac{7}{36}):(- \frac{7}{24})+0,(6)]-2,1(6)-0,41(6) = \\ \\ \([( \frac{81}{288}- \frac{60}{288}-\frac{56}{288})*(- \frac{24}{7} )+ \frac{2}{3}]-2 \frac{1}{6}- \frac{5}{12} = \\ \\ \([- \frac{35}{288}*(- \frac{24}{7})+ \frac{2}{3}]- ^{2)}\frac{13}{6}- \frac{5}{12}= \\ \\ ( \frac{5}{12}+ ^{4)}\frac{2}{3} )- \frac{26}{12}- \frac{5}{12}= \\ \\ \frac{5}{12}+ \frac{8}{12}- \frac{31}{12} = - \frac{18}{12}^{(6}=\boxed{- \frac{3}{2}} [/tex]