Question

!!!!!!!!!!Exercițiul 1 și 2

Answer 1

1)√32=4√2 ;√50=5√2 ;√20=2√5 ;√27=3√3 ;√72=6√2; √125=5√5 ;√200=10√2 ;√242=11√2 ;√147=7√3 ;√162=9√2 ;√768=16√3
2)[tex] \sqrt{ \frac{27}{49}} = \frac{3 \sqrt{3} }{7} ; \sqrt{7 \frac{7}{48} }= \sqrt{ \frac{343}{48} } = \frac{7 \sqrt{7} }{4 \sqrt{3} } \\ \sqrt{ \frac{0,25}{6} }= \sqrt{ \frac{1}{24} }= \frac{1}{2 \sqrt{6} } \\ \sqrt{5^5}=5^2 \sqrt{5} \\ \sqrt{ (\frac{2}{3})^3 }= \frac{2}{3} \sqrt{ \frac{2}{3} } [/tex]