Question

Exercitiul 1 va rog! 25 de puncte!

Answer 1

$23 + {3}^{26} \div {27}^{8} - {({(6 + 2 \times 5)}^{10})}^{2} \div {8}^{ {5}^{2} } \times {(4 - 16 \div 8)}^{0} \\ 23 + {3}^{26} \div {3}^{24} - {( {16}^{10}) }^{2} \div {8}^{25} \times 1 \\ 23 + {3}^{2} - {16}^{20} \div {2}^{75} \\ 23 + 9 - {2}^{80} \div {2}^{75} \\ 32 - {2}^{5} = 32 - 32 =0$