Question

Exercitiul 1 va rog.

Answer 1

Răspuns:

Explicație:

MCu2O=2. 64  + 16=144--------> 144g/moli

MCa(OH)2= 40 + 2.16 +2=74-------> 74g/moli

MH2SO3= 2+32 +3.16=82-------->82g/moli

MCaCO3= 40 + 12 + 3.16=100------> 100g/moli

Answer 2

oxid de cupru I = Cu2O

M.Cu2O = 2x64+16 = 144 g/mol

hidroxid de calciu = Ca(OH)2

M.Ca(OH)2 = 40+2(16+1) = 74 g/mol

acid sulfuros = H2SO3

M.H2SO3 = 2x1+32+3x16 = 82 g/mol

carbonat de calciu = CaCO3

M.CaCO3 = 40+12+3x16 = 100 g/mol