Question

Exercitiul 10 (b,d,f)
Va rogggg

Answer 1

B)
$\frac{11x - 4}{4} + \frac{1 - x}{2} = 6 - x$
Aducem la acelasi numitor comun si anume

$\frac{11x - 4 + 2 - 2x}{4} = \frac{4 \times (6 - x)}{4}$
$9x - 2 = 24 - 4x \\ 9x + 4x = 24 + 2 \\ 13x = 26 \\ x = 26 \div 13 \\ x = 2$

D)
$\frac{x + 2}{3} - \frac{2x + 3}{4} + \frac{5}{3} = 1 \frac{5}{6} + \frac{7x - 11}{12}$

$\frac{x + 2}{3} - \frac{2x + 3}{4} + \frac{5}{3} = \frac{1 \times 6 + 5}{6} + \frac{7x - 11}{12}$


$\frac{4 \times (x + 2) - 3 \times (2x + 3) + 4 \times 5}{12} =$
$= \frac{11 \times 2 + 7x - 11}{12}$


$\frac{4x + 8 - 6x - 9 + 20}{12} = \frac{22 + 7x - 11}{12}$

-2x+19=11+7x
19-11=7x+2x
8=9x
X=8/9


F)
$\frac{7x - 12}{5} + \frac{19 - 6x}{7} = \frac{x}{2} + \frac{x - 1}{5}$


$\frac{14 \times (7x - 12) + 10 \times (19 - 6x)}{70} =$

$= \frac{35x + 14 \times (x - 1)}{70}$
98x-168+190-60x=35x+14x-14
38x+22=49x-14
22+14=49x-38x
36=11x
X=36/11