Question

Exercitiul 10 prima ecuatie,va rog

Answer 1

a/4=b/6 => b=3a/2

a/4=c/8 => c=2a

inlocuiesti in a doua si ai ca:

1/a+1/(3a/2)+1/(2a)=13/144

Dai 1/a factor comun

1/a(1+2/3+1/2)=13/144

1/a(13/6)=13/144

1/a=13/144:13/6

1/a=1/24

a=24

b=36

c=48