Question

Exercitiul 10 va rog frumos

Answer 1

PALMITATUL DE SODIU :CH3-(CH2)14-COONa..M= 278g/mol
n=m/M; n=55,6g/278g/mol=0,2mol---. >rezulta din 0,1mol triglicerida si 0,2mol NaOH
OLEATUL DE SODIU :CH3-(CH2)7-CH=CH-(CH2)7-COONa, M=3O4g/mol
n=m/M; n= 30,4g/304g/mol=0,1mol------> rezulta din 0,1mol triglicerida si 0,1molNaOH
TOTAL: 0,3molNaOH---> M= NXm---> m=0,3molx40g/mol=12g NaOH
C/100= md/ms; 20/100=12/ms----------------> calculeaza ,ms!!!!

trigliceridele pot fi:
1,2 dipalmitil 3 oleil glicerol
1,3 dipalmitil 2 oleil glicerol
1 oleil  2,3 dipalmitil glicerol