Question

exercitiul 13, va rog ! e urgent !

Answer 1

3(x-1)+2(y+4)=24
3(y+1)+x²=(x+1)(x-1)-2x

3x-3+2y+8=24
3y+3+x²=x²-1-2x

3x+2y=19      y=(19-3x)/2
2x+3y=-4     
2x+3(19-3x)/2=-4 
4x+57-9x=-8 
5x=65
x=13
y=(19-3*13)/2=(19-39)/2=-10


3(2x-3)+3(5+y)=15
5(4x-3)-2(y+3)=3

6x-9+15+3y=15
20x-15-2y-6=3

6x+3y=9
20x-2y=24

2x+y=3        y=3-2x
10x-y=12
10x-3+2x=12
12x=15
x=15/12=5/4
y=3-2*5/4=3-5/2=1/2