Question

Exercitiul 14 pls help

Answer 1

Răspuns:

Explicație pas cu pas:

a)

= 2^2015 x (2^2 - 2 - 1) : 2^5 : (2^4)^502 + 1 x 1

= 2^2015 x 1 : 2^5 : 2^2008 + 1

= 2^(2015 - 5 - 2008) + 1

= 2^2 + 1

= 4 + 1

= 5

b)

= ( 1 + (3^3)^27 : (3^2)^40)^50 : 32^20

= (1 + 3^81 : 3^80)^50 : 32^20

= (1 + 3)^50 : 32^20

= 4^50 : 32^20

= (2^2)^50  : (2^5)^20

= 2^100 : 2^100

= 1

c)

= 2^8 : 4^3 + 3^4 : (64 - 36 - 1)

= 2^8 : (2^2)^3 + 3^4 : 27

= 2^8 : 2^6 + 3^4 : 3^3

= 2^2 + 3

= 4 + 3

= 7