Question

Exercitiul 14 va rog, multumesc!

Answer 1

Vs1 = 100mL sol. H2SO4
C1 = 25%
ro1(densitatea) = 1,18g/cm^3
Vs2 = 500mL sol. H2SO4
C2 = 0,5M
Vs3 = 200mL sol. H2SO4
C3 = 1M

Cf = ? M

ro1 = ms1/Vs1 => ms1 = ro1×Vs1 = 1,18×100 = 118g sol. H2SO4

C1 = md1/ms1×100 => md1 = C1×ms1/100 = 25×118/100 = 29,5g H2SO4

C2 = md2/M×Vs2(L) => md2 = C2×M×Vs2 = 0,5×98×0,5 = 24,5g H2SO4

C3 = md3 /M×Vs3(L) => md3 = 1×98×0,2 = 19,6g H2SO4


md final = md1+md2+md3 = 29,5+24,5+19,6 = 73,6g H2SO4

Vsf = Vs1+Vs2+Vs3 = 100+500+200 = 800mL = 0,8 L

n total = mdf/M = 73,6/98 = 0,751 moli H2SO4

Cf = n total/Vsf(L) = 0,751/0,8 = 0,938M