Question

Exercitiul 16 punctul a)
Dau coroana

Answer 1

[(5+3√2)/3√2-(9+2√2)/2√2] ×(6√2/√3-3/2√6+6√3/3√2-4√3/2√2)=
=(5/3√2+1-9/2√2-1) ×(6√6/3-3√6/12+6√6/6-4√6/4)=
=(5√2/6-9√2/4) ×(2√6-√6/4+√6-√6)=
=(10√2-27√2)/12 ×(8√6-√6)/4=
=(-17√2)/12 ×7√6/4=
=-119√12/48=
=-119×2√3/48=
=-119√3/24