Question

Exercitiul 2,dau coroana

Answer 1

I2x+3I≤9⇒2x+3≤9⇒2x≤6⇒x≤3 (1) si -2x-3≤9⇒-2x≤12⇒x≥6 (2)
din (1) si (2)⇒x∈[-6,3]⇒A={-6,-5,-4,-3,-2,-1,0,1,2,3}
-1<(3x+7)/2⇒-2<3x+7⇒x>-3 (1)
(3x+7)/2≤11⇒3x+7≤22⇒x≤5 (2) din (1) si (2)⇒
x∈(-3,5]⇒B={-2,-1,0,1,2,3,4,5}
AnB={-2,-1,0,1,2,3}
B/A={4,5}