Question

exercitiul 2 de la subiectul al 2 lea, va rog.

Answer 1

$\frac{3a-2b}{b} =10\ \textless \ =\ \textgreater \ \frac{3a}{b} - \frac{2b}{b} =10\ \textless \ =\ \textgreater \ \frac{3a}{b} -2=10$
$\frac{3a}{b} =12=\ \textgreater \ 3a=12b=\ \textgreater \ a=4b,sau, \frac{a}{b} =4$