Question

Exercițiul 2 rapid. Ofer 15 puncte. Repedeeee!!!

Answer 1

Răspuns

2a/3 = 5b/6 = 8c/9  si a + b + c = 51

2a/3 = k⇒ a = 3k/2

5b/ 6 = k⇒ b = 6k/5

8c/9 = k ⇒ c = 9k/8

3k/2 + 6k/5 + 9k/8 = 51

3·4·5·k + 8·6·k + 5·9·k = 51·40

60 k + 48 k + 45 k = 2040

153 k = 2040

k = 2040 / 153

a = 3k/2= (3·2040)/(2·153) = 20

b = 6k/5=(6·2040)/(5·153) = 16

c = 9k / 8 = (9·2040)/(8·153) = 15

deci a = 20;  b = 16   si c = 15