Question

Exercițiul 2 si 3 Varianta I
Repejor vă rog

Answer 1

Răspuns:

Ex3 varianta 1

3x-2y-xy-3=0

Adui si   scazi 9 in ambii  membrii

3x-2y-xy-3+9=9

3x-2y-xy+6=9

(3x-xy)+(-2y+6)=9

x(3-y)+2(3-y)=9

(3-y)(x+2)=9

Caz 1

3-y= -9  y=12

x+2= -1   x= -3

(-3;12)

Caz2

3-y= -3 y= 6

x+2= -3  x= -5

(-5;6)

----------------

caz3

3-y= -1   y=4

x+2= -9 x= -11

(-11,4)

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Caz 4

3-y=1   y=2

x+2=9   x=7

(2,7)

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caz 5

3-y=3  y=0

x+2=3  x=1

(1;0)

-----------------------------

Caz 6

3-y=9  y= -6

x+2=1    x= -1

(-1,-6)

Ex 2 V 1

P(x)=x⁵+7x³+2x²-3x-1

Q(x)=x-2

restul?

Qx=0  x-2=0    

x=2

P(2)=2⁵+7*2³+2*2²-3*2-1=

32+7*8+2*4-6-1

32+56+8-7=

88+1=89

Explicație pas cu pas: