Matematică, întrebare adresată de jsjjnrndjsk, 8 ani în urmă

Exercițiul 2 va rog mult
Dau corona

Anexe:

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Răspuns de Absteiger
0

Explicație pas cu pas:

a) \frac{9}{4} +  \frac{3}{2} =  \frac{9}{4} +  \frac{3 \times 2}{2 \times 2} =  \frac{9}{4} +  \frac{6}{4} =  \frac{9 + 6}{4} =  \frac{15}{4} = 3 \frac{3}{4}

b) \frac{5}{6} -  \frac{4}{3} =  \frac{5}{6} -  \frac{4 \times 2}{3 \times 2} =  \frac{5}{6} -  \frac{8}{6} =  \frac{5 - 8}{6} =  -  \frac{3}{6} ^{(2} =  -  \frac{1}{2}

c) \frac{7}{6} +  \frac{5}{4} =  \frac{7 \times 2}{6 \times 2} +  \frac{5 \times 3}{4 \times 3} =  \frac{14}{12} +  \frac{15}{12} =  \frac{14 + 15}{12} =  \frac{29}{12} = 2 \frac{5}{12}

d) \frac{7}{4} -  \frac{8}{5} =  \frac{7 \times 5}{4 \times 5} -  \frac{8 \times 4}{5 \times 4} =  \frac{35}{20} -  \frac{32}{20} =  \frac{35 - 32}{20} =  \frac{3}{20}

e)2 \frac{3}{8} + ( -  \frac{13}{6}) =  \frac{19}{8} + ( -  \frac{13}{6}) =  \frac{19 \times 3}{8 \times 3} +  \frac{( - 13) \times 4}{6 \times 4} =  \frac{57}{24} + ( -  \frac{52}{24}) =  \frac{57 + ( - 52)}{24} =  \frac{5}{24}

f)( -  \frac{7}{4}) - 1 \frac{3}{14} =  -  \frac{7}{4} -  \frac{17}{14} =  \frac{ - 7 \times 7}{4 \times 7} -  \frac{17 \times 2}{14 \times 2} =  -  \frac{49}{28} -  \frac{34}{28} =  \frac{ - 49 - 34}{28} =  -  \frac{83}{28} =  - 2 \frac{27}{28}

g)( -  \frac{11}{12}) - 1 \frac{4}{9} =  -  \frac{11}{12} -  \frac{13}{9} =  \frac{ - 11 \times 3}{12 \times 3} -  \frac{13 \times 4}{9 \times 4} =  -  \frac{33}{36} -  \frac{52}{36} =  \frac{ - 33 - 52}{36} =  -  \frac{85}{36} =  - 2 \frac{13}{36}

h)( - 2 \frac{1}{8}) +  \frac{9}{10} =  -  \frac{17}{8} +  \frac{9}{10} =  \frac{ - 17 \times 5}{8 \times 5} +  \frac{9 \times 4}{10 \times 4} =  -  \frac{85}{40} +  \frac{36}{40} =  \frac{ - 85 + 36}{40} =  -  \frac{49}{40} =  - 1 \frac{9}{40}

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