Question

Exercitiul 21 va rog!!! Dau coroana!!!

Answer 1

Răspuns:

Din datele problemei:

Ma = (a+b+c+d)/4 = 32 intregi si 1/4 => (a+b+c+d)/4 = 129/4 => a+b+c+d = 129

Ma = (a+b)/2 = 17 intregi si 1/2 => (a+b)/2 = 35/2 => a+b = 35

a = 75%*b

a = 25%*d

Rezolvare:

a= 75%*b = 75/100*b = 3/4*b

a+b=35 => 3/4*b+b=35 (aducem la acelasi numitor) => 3/4*b+4*b=35*4 => 3b+4b=140 => 7b =140 => b=20

a =3/4b = 3/4*20 = 15

a=25%*d => 15 = 25/100*d => 15 = 1/4*d => d = 60

a+b+c+d=129 => 15+20+c+60=129 => c+95=129 => c=129-95 => c=36

a=15

b=20

c=36

d=60