Question

Exercițiul 29 repedeeee va roooog

Answer 1

a)
(2ab²)³×(3a⁻¹b)²:(36ab⁷)=
=8a³b⁶×(9b²/a²):(36ab⁷)=
=72ab⁸:36ab⁷=2b

b)
(2a⁻¹b/3)²×(3a²b³)³:(a⁻³b⁻¹⁰/2)⁻¹=
=(2b/3a)²×(27a⁶b⁹):(1/2a³b¹⁰)⁻¹=
=4b²/9a²×27a⁶b⁹:2a³b¹⁰=
=12b¹¹a⁴:2a³b¹⁰=
=6ab

c)
(3ab³/4)²×(a²b⁻²/6)⁻¹ :(3b⁴/2)²=
=9a²b⁶/16×6/a²b⁻²) :9b⁸/4=
=9a²b⁶/16×6b²/a² ×4/9b⁸=
=27b⁸/8 × 4/9b⁸=
=3/2