Question

Exercitiul 3!!!!Cel cu functia!!!

Answer 1

a)A(3,2)∈Gf⇒f(3)=2
f(x)=ax+5
f(3)=3a+5
2=3a+5
3a=2-5
a=-3/3
a=-1

b)a=1⇒f(x)=x+5
Gf∩Ox⇒y=0⇒x+5=0⇔x=-5⇒A(-5,0)
Gf∩Oy⇒x=0⇒f(0)=5⇒B(0,5)
AΔAOB=AO*OB/2=5*5/2=25/2cm²