Question

Exercitiul 3. Multumesc

Answer 1

Răspuns:

Explicație pas cu pas:

$2^{2x}-2^{x+1} = 3\\\left(2^x\right)^2-2^x\cdot \:2^1=3\\2^x=u\\\left(u\right)^2-u\cdot \:2^1=3\\u^2-2u-3=0\\u=3,\:u=-1\\2^x=3 =>\ln \left(2^x\right)=\ln \left(3\right) =>x\ln \left(2\right)=\ln \left(3\right)\\x=\frac{\ln \left(3\right)}{\ln \left(2\right)}\\2^x=-1 => x\notin \mathbb{R}$