Question

Exercitiul 3 si 4 VA ROG!! URGENT!!! DAU COROANA ​

Answer 1

Răspuns:

3.

H2+Cl2=> 2HCl

2Li+ Cl2=> 2LiCl

2Ba+Cl2 => BaCl2

2Fe+ 3Cl2 =>2 FeCl3

4.

NCl2 =2×35,5=71g/mol

m=4×71=284g

MLiCl=7+35,5+7=42,5g/mol

71g 2×42,5g

2Li+ Cl2=> 2LiCl

284g xg

x=284×2×42,5/71=calculează

MBaCl2=137+2×35,5=208g/mol

71g 208g

2Ba+Cl2 => BaCl2

284g yg

y=284×207/71=calculează

MFeCl3= 56+3×35,5=162,5g/mol

3×71g 2×162,5g

2Fe+ 3Cl2 =>2 FeCl3

284g zg

z=284×2×162,5/3×71=calculează