Question

Exercitiul 3 va rog .......

Answer 1

[tex]\overline{bc}=9a\\ \overline{bca}=\overline{abc}-108\\ 10\overline{bc}+a=100a+\overline{bc}-108\\ 90a+a=100a+9a-108\\ 109a-91a=108\\ 18a=108\\ a=6\\ \overline{bc}=9a=54\\ \overline{abc}=654[/tex]

Answer 2

bc=9a
bca=abc-108
100b+10c+a+108=100a+10b+c
90b+9c+108=99a
10b+c+12=11a
bc+12=11a
bc=9a          
9a+12=11a
12=2a
a=6
bc=6*9=54 rezulta ca 
abc=654