Question

exercitiul 3!!!!! va rog

Answer 1

   
[tex]\displaystyle\\ \sqrt{2x^2+1}=1~~~\text{(Ridicam la puterea a 2-a.)}\\\\ \Big(\sqrt{2x^2+1}\Big)^2=\Big(1\Big)^2\\\\ 2x^2+1=1\\\\ 2x^2+1-1=0\\\\ 2x^2=0\\\\ x^2 =\frac{0}{2}\\\\ x^2=0\\\\ x=\pm\sqrt{0}=\pm~0\\\\ \boxed{x_1=0}\\\\ \boxed {x_2=0}\\\\ \text{In fisierul atasat gasesti graficul functiei atasate acestei ecuatii:}\\\\ f(x)=\sqrt{2x^2+1}-1\\\\ \text{din care se vede ca f(x) = 0 are doua solutii egale (confundate)}\\ \text{deoarece graficul este tangent la axa Ox in punctul} ~~~x=0.[/tex]