Question

Exercițiul 3,Va rog!!!!!!!

Answer 1

a) (x+1)/3 = -1/2 + x/6
    2(x+1)/6 = -3/6 + x/6
    2(x+1) = -3+x
    2x+2 = -3+x
    2x-x = -3-2
    x = -5
b) 1/10 - (x+1)/2 = (x-2)/5
    1/10 - 5(x+1)/10 = 2(x-2)/10
    1 - 5(x+1) = 2(x-2)
    1 - 5x - 5 = 2x - 2
     -5x-2x = -2-1+5
     -7x = 2
      x = -2/7
c) (2-x)/6 = 1,(1) - (x+2)/3
    (2-x)/6 = 10/9 - (x+2)/3
    3(2-x)/18 = 20/18 - 6(x+2)/18
    3(2-x) = 20 - 6(x+2)
    6 - 3x = 20 - 6x - 12
    -3x + 6x = 8-6
    3x = 2
    x = 2/3
d) (2x-1)/4 + (1-x)/3 = -x/6
    3(2x-1)/12 + 4(1-x)/12 = -2x/12
    6x - 3 + 4 - 4x = -2x
    2x+2x = -1
    4x = -1
    x = -1/4
e) x/21 + (x-2)/3 = (x-3)/7
    x/21 + 7(x-2)/21 = 3(x-3)/21
    x + 7x - 14 = 3x - 9
    8x - 3x = -9+14
    5x = 5
    x = 1
f) (x+2)/4 + (2x+1)/12 = (x-1)/3
   3(x+2)/12 + (2x+1)/12 = 4(x-1)/12
   3x + 6 + 2x + 1 = 4x - 4
   5x - 4x = -4-7
   x = -11