Question

Exercitiul 3 va rog.

Answer 1

Răspuns: Ai mai jos rezolvarea pentru fiecare sub-punct in parte

Salutare!

( A )

$\bf (x+2)^{2}=x^{2} +2\cdot 2x +2^{2} = \boxed{\bf x^{2} +4x +4}$

( B )

$\bf \Big(\dfrac{1}{3} x-1 \Big)^{2}=\dfrac{x^{2}}{9} -2\cdot\dfrac{1}{3}x\cdot 1 +1^{2} = \boxed{\bf \dfrac{x^{2}}{9} -\dfrac{2x}{3} +1}$

( C )

$\bf (2\sqrt{2} +\sqrt{3}x)^{2}=(2\sqrt{2})^{2} +2\cdot2\sqrt{2}\cdot \sqrt{3}x +(\sqrt{3}x)^{2} = \boxed{\bf 8+4\sqrt{6}x +3x^{2} }$

==pav38==