Question

Exercitiul 3 va rog frumos
Dau coroana

Answer 1

$\frac{9 \times (2x + 1)}{21} - \frac{2 \times (2x + 10)}{12} = \frac{6x - 6}{42} - \frac{5 \times (2x + 2)}{28} \\ \frac{18x + 9}{21} - \frac{4x + 20}{12} = \frac{6x - 6}{42} - \frac{10x + 10}{28} \\ \frac{4 \times (18x + 9)}{84} - \frac{7 \times (4x + 20)}{84} = \frac{2 \times (6x - 6)}{84} - \frac{3 \times (10x + 10)}{84} \\ \frac{72x + 36}{84} - \frac{28x + 140}{84} = \frac{12x - 12}{84} - \frac{30x + 30}{84} \\ \frac{72x + 36 - 28x - 140}{84} = \frac{12x - 12 - 30x - 30}{84} \\ \frac{44x - 104}{84} = \frac{ - 18x - 18}{84} \\ 44x - 104 = - 18x - 18 \\ 44x + 18x = - 18 + 104 \\62x = 96 \\ x = \frac{96}{62} \\ x = \frac{48}{31}$
$| |2x - 3| - 3| = 6 \\ 1) |2x - 3| - 3 = 6 \\ |2x - 3| = 6 + 3 \\ |2x + 3| = 9 \\ 1)2x + 3 = 9 \\ 2x = 9 - 3 \\ 2x = 6 \\ x = 3 \\ 2) |2x - 3| - 3 = - 9 \\ |2x - 3| = - 9 + 3 \\ |2x - 3| = - 6 \\ x = - 3 \\ 2) |2x - 3| - 3 = - 6 \\ |2x - 3| = - 6 + 3 \\ |2x - 3| = - 3 \\ \\ ecuatia \: nu \: are \: solutii \: cu \: - 6 \: deci \: numerele \: din \: modul \: \: au \: care \: rezultat \: un \: numar \: par$