Question

exercițiul 3 va rogg,cu toata rezolvarea!UrgentDau coroana❤️​

Answer 1

Răspuns:

a) [(5x)²-7²]-[(4x)²-2*4x*3+3²) ]-[(3x)²+2*3x*2+2²]-12x+24=

(25x²-49)-(16x²-24x+9)-(9x²+12x+4) -12x+24=

25x²-49-16x²+24x-9-9x²-12x-4-12x+24=

25x²-16x²-9x²-62+24-12x-12x=

-38

b) 15x²-1-(9x²+12x+4) -(6x²+9) +12x+20=

15x²-1-9x²-12x-4-6x²-9+12x+20=

6

c) 9x²-12x+4-4x²+25-5(x²+2x+1) =

5x²-12x+29-5x²-10x-5=

-22x+24

d) (4x²+25) -[x(x-2)+3(x-2) ]-3(x²+4x+4) =

(4x²+25) -(x²-2x+3x-6) -3x²-12x-12=

4x²+25-x²+x+6-3x²-12x-12=

19-11x

e) 2[x(x-1)+5(x-1)]-(x²+4x+4) -x²-25=

2(x²-1+5x-5) -x²-4x-4-x²-25=

2(x²-6+5x) -2x²-4x-29=

2x²-12+10x-2x²-4x-29=

-41+6x

f) (9x²+24x+16)-6[x(x+4) +2(x+4)]-3(x²-16) =

(9x²+24x+16)-6(x²+4x+2x+8) -3x²+48=

(9x²+24x+16)-6(x²+6x+8) -3x²+48=

9x²+24x+16-6x²-36x-48-3x²+48=

-12x+16