Question

exercitiul 38....e foarte important nu înțeleg

Answer 1

A=3^n*2^2n*3*2^3 +3^(n+2)*2^(2n+2) +2^(n+3)*2^n*3^n=

2^(2n+3)*3^(n+1)+2^(n+2)*3^(n+2)+2^(2n+3)*3^n=

2^(2n+2)*3^n (2*3+3^2+2)=

2^(2n+2)*3^n*17  

=> A e divizibil cu 17