Question

exercitiul 4 plsss
repede

Answer 1

$( 2^{3} ) ^{5} : 4^{6} + 3^{0} =$
[tex] 2^{15} :( 2^{2} ) ^{6} +1= [/tex]
$2^{15} : 2^{12} +1=$
[tex] 2^{15-12} +1= [/tex]
$2^{3} +1=8+1=9$