Question

EXERCIȚIUL 4!!!!!!!!! (sunt cl VI) ​

Answer 1

x+y+z = 180
{x,y,z} d.p {3,7,8} => x/3 = y/7 = z/8 = k

x/3 = k => x = 3k
y/7 = k => y = 7k
z/8 = k => z = 8k

3k+7k+8k = 180
18k = 180 | : 18
k = 10

x = 3k = 3 x 10 = 30
y = 7k = 7 x 10 = 70
z = 8k = 8 x 10 = 80

Answer 2

Explicație pas cu pas:

Bună!

$\frac{x}{3} = \frac{y}{7} = \frac{z}{8} = k$

$= > x + y + z = 180$

$= > x = 3k \\ y = 7k \\ z = 8k$

$acum \: inlocuim \\ 3k + 7k + 8k = 180 \\ 18k = 180 = > k = 10$

$acum \: aflam \: numerele \: x \: y \: z$

$= > x = 10 \times 3 = 30 \\ = > y = 10 \times 7 = 70 \\ = > z = 10 \times 8 = 80$

Succes!

~yourhelper087~